TPAT-1 Tests - เชาวน์ปัญญา

Let's solve this step by step:

Let's say the cow costs x baht and the sheep costs (9000-x) baht
Profit from cow = 0.3x
Profit from sheep = 0.4(9000-x)
Total profit = 3100
Therefore: 0.3x + 0.4(9000-x) = 3100
0.3x + 3600 - 0.4x = 3100
-0.1x + 3600 = 3100
-0.1x = -500
x = 5000

So the cow costs 5000 baht.

{"correct_answer_key":"c"}

Let me solve this step by step:

Let's say the cost of the cow is x baht and the cost of the sheep is (9000-x) baht.

When selling the cow with 30% profit, the profit is 0.3x baht. When selling the sheep with 40% profit, the profit is 0.4(9000-x) baht.

The total profit is 3,100 baht, so: 0.3x + 0.4(9000-x) = 3100 0.3x + 3600 - 0.4x = 3100 -0.1x + 3600 = 3100 -0.1x = -500 x = 5000

Therefore, the cow was bought for 5,000 baht, which corresponds to option C.

{"correct_answer_key":"c"}

Let's break down the problem in English:

"I bought a cow and a sheep for a total of 9,000 baht. I sold the cow at a profit of 30% and the sheep at a profit of 40%. The total profit was 3,100 baht. What was the purchase price of the cow?"

Let's denote:

x = purchase price of the cow (in baht)
y = purchase price of the sheep (in baht)

We have the following equations:

x + y = 9,000 (total purchase price)
0.3x + 0.4y = 3,100 (total profit)

Let's solve this system of equations.

From equation 1, we have: y = 9,000 - x

Substituting this into equation 2: 0.3x + 0.4(9,000 - x) = 3,100 0.3x + 3,600 - 0.4x = 3,100 0.3x - 0.4x + 3,600 = 3,100 -0.1x + 3,600 = 3,100 -0.1x = 3,100 - 3,600 -0.1x = -500 x = 5,000

Therefore, the purchase price of the cow is 5,000 baht.

Let's double-check:

Purchase price of cow = 5,000 baht
Purchase price of sheep = 9,000 - 5,000 = 4,000 baht
Profit on cow = 0.3 × 5,000 = 1,500 baht
Profit on sheep = 0.4 × 4,000 = 1,600 baht
Total profit = 1,500 + 1,600 = 3,100 baht ✓

The answer is 5,000 baht, which corresponds to option "c".

I need to find the price of the cow in this Thai word problem.

Given:

Bought a cow and sheep for 9,000 baht total
Cow was sold at 30% profit
Sheep was sold at 40% profit
Total profit was 3,100 baht

Let me solve: If the cow costs x baht and sheep costs y baht:

x + y = 9,000
0.3x + 0.4y = 3,100

Substituting y = 9,000 - x: 0.3x + 0.4(9,000 - x) = 3,100 0.3x + 3,600 - 0.4x = 3,100 -0.1x = -500 x = 5,000

The cow costs 5,000 baht, which corresponds to option C.

{"correct_answer_key":"c"}

Let's denote the cost price of the cow as ( C ) and the cost price of the sheep as ( S ). We know the following:

The total cost of the cow and sheep is: [ C + S = 9,000 ]
The profit from selling the cow is 30%, so the selling price of the cow is: [ 1.3C ]
The profit from selling the sheep is 40%, so the selling price of the sheep is: [ 1.4S ]
The total profit is: [ (1.3C - C) + (1.4S - S) = 3,100 ] [ 0.3C + 0.4S = 3,100 ]

Now we have a system of linear equations: [ \begin{cases} C + S = 9,000 \ 0.3C + 0.4S = 3,100 \end{cases} ]

First, solve the first equation for ( S ): [ S = 9,000 - C ]

Substitute ( S ) into the second equation: [ 0.3C + 0.4(9,000 - C) = 3,100 ] [ 0.3C + 3,600 - 0.4C = 3,100 ] [ -0.1C + 3,600 = 3,100 ] [ -0.1C = 3,100 - 3,600 ] [ -0.1C = -500 ] [ C = \frac{-500}{-0.1} ] [ C = 5,000 ]

Thus, the cost price of the cow is 5,000 baht, which corresponds to option C.

{"correct_answer_key":"c"}

Explanation:

Let’s break down the problem step by step:

Define Variables:
- Let ( x ) = price of the cow (วัว).
- Let ( y ) = price of the sheep (แกะ).
Given Equations:
- The total purchase price:
  ( x + y = 9000 ) ...(1)
- The total profit from selling both:
  ( 0.3x + 0.4y = 3100 ) ...(2)
  (30% profit on cow, 40% profit on sheep)
Solve the Equations:
- From equation (1):
  ( y = 9000 - x ).
- Substitute ( y ) into equation (2):
  ( 0.3x + 0.4(9000 - x) = 3100 ).
  Simplify:
  ( 0.3x + 3600 - 0.4x = 3100 ).
  ( -0.1x = -500 ).
  ( x = 5000 ).
Conclusion:
- The cow was bought for 5,000 baht (option C).

Answer in JSON:

{"correct_answer_key":"c"}

Okay, let's see. The problem is about buying a cow and a sheep for a total of 9,000 baht. Then selling them with a profit of 30% on the cow and 40% on the sheep, making a total profit of 3,100 baht. We need to find the original price of the cow.

First, let's set up variables. Let me call the cost price of the cow as C and the sheep as S. According to the problem, C + S = 9,000. That's straightforward.

Now, the profit from selling the cow is 30% of C, which is 0.3C. The profit from the sheep is 40% of S, which is 0.4S. The total profit is 3,100 baht, so 0.3C + 0.4S = 3,100.

We have two equations here:

C + S = 9,000
0.3C + 0.4S = 3,100

We need to solve these two equations to find C. Let's solve the first equation for S: S = 9,000 - C. Then substitute this into the second equation.

Substituting S in the second equation: 0.3C + 0.4(9,000 - C) = 3,100

Let's expand that: 0.3C + 0.49,000 - 0.4C = 3,100 Calculate 0.49,000 = 3,600 So, 0.3C + 3,600 - 0.4C = 3,100

Combine like terms: -0.1C + 3,600 = 3,100

Subtract 3,600 from both sides: -0.1C = 3,100 - 3,600 -0.1C = -500

Divide both sides by -0.1: C = (-500)/(-0.1) = 5,000

So the cost price of the cow is 5,000 baht. Checking the options, option c is 5000. Let me verify.

If C is 5,000, then S is 4,000. Profit from cow: 0.35,000=1,500. Profit from sheep: 0.44,000=1,600. Total profit: 1,500+1,600=3,100. That matches the given total profit. So the answer is c.

{"correct_answer_key":"c"}

The question is in Thai and asks: "A cow and a sheep were bought, totaling 9,000 baht. The cow was sold for a 30% profit and the sheep was sold for a 40% profit. The total profit was 3,100 baht. Find the purchase price of the cow."

Let 'c' be the price of the cow and 's' be the price of the sheep. We can set up the following equations:

c + s = 9000 (The total cost of the cow and sheep)
0.30c + 0.40s = 3100 (The total profit from selling the cow and sheep)

We can solve this system of equations. One way is to solve the first equation for 's' (s = 9000 - c) and substitute it into the second equation:

0.30c + 0.40(9000 - c) = 3100 0.30c + 3600 - 0.40c = 3100 -0.10c = -500 c = 5000

Therefore, the price of the cow is 5000 baht.

{"correct_answer_key": "c"}

Let 'x' be the price of the cow and 'y' be the price of the sheep. We have two equations:

x + y = 9000
0.3x + 0.4y = 3100

We can solve this system of equations. From equation (1), we get y = 9000 - x. Substituting this into equation (2):

3x + 0.4(9000 - x) = 3100
3x + 3600 - 0.4x = 3100 -0.1x = -500 x = 5000

Therefore, the price of the cow is 5000.

{"correct_answer_key":"c"}

Let's break down the problem. We know the combined cost of a cow and a sheep is 9000 baht. We also know the total profit from selling them is 3100 baht. We need to find the original price of the cow.

Let 'x' be the cost of the cow and 'y' be the cost of the sheep. We have two equations:

x + y = 9000
0.3x + 0.4y = 3100 (30% profit on cow + 40% profit on sheep = total profit)

We can solve this system of equations. From equation 1, we can express y as y = 9000 - x. Substitute this into equation 2:

3x + 0.4(9000 - x) = 3100
3x + 3600 - 0.4x = 3100 -0. 1x = -500 x = 5000

Therefore, the cost of the cow is 5000 baht.

{"correct_answer_key":"c"}

Explanation: Let the price of the cow be 'x' and the price of the sheep be 'y'. From the problem, we have two equations:

x + y = 9000 (Total cost of cow and sheep)
0.30x + 0.40y = 3100 (Total profit from selling cow and sheep)

From equation 1, we can express y as y = 9000 - x. Substitute this into equation 2: 0.30x + 0.40(9000 - x) = 3100 0.30x + 3600 - 0.40x = 3100 -0.10x = 3100 - 3600 -0.10x = -500 x = -500 / -0.10 x = 5000

Therefore, the original price of the cow is 5000 baht.

{"correct_answer_key":"c"}

Let C be the purchase price of the cow and S be the purchase price of the sheep. We are given that the total purchase price is 9,000 baht: C + S = 9000

The profit from selling the cow is 30% of C, which is 0.30C. The profit from selling the sheep is 40% of S, which is 0.40S. The total profit is 3,100 baht: 0.30C + 0.40S = 3100

We have a system of two equations:

C + S = 9000
0.3C + 0.4S = 3100

From equation 1, we can express S as S = 9000 - C. Substitute this into equation 2: 0.3C + 0.4(9000 - C) = 3100 0.3C + 3600 - 0.4C = 3100 3600 - 0.1C = 3100 3600 - 3100 = 0.1C 500 = 0.1C C = 500 / 0.1 C = 5000

The purchase price of the cow is 5,000 baht. This corresponds to option c.

{"correct_answer_key":"c"}

Let the cost of the cow be C and the cost of the sheep be S. We are given that C + S = 9000. The profit from selling the cow is 30% of C, which is 0.30C. The profit from selling the sheep is 40% of S, which is 0.40S. The total profit is 3100, so 0.30C + 0.40S = 3100.

We have a system of two linear equations:

C + S = 9000
0.30C + 0.40S = 3100

From equation 1, we can express S as S = 9000 - C. Substitute this into equation 2: 0.30C + 0.40(9000 - C) = 3100 0.30C + 3600 - 0.40C = 3100 -0.10C = 3100 - 3600 -0.10C = -500 C = -500 / -0.10 C = 5000

So, the cost of the cow is 5000 baht.

{"correct_answer_key":"c"}

Let C be the purchase price of the cow and S be the purchase price of the sheep. We are given two equations:

C + S = 9000 (Total cost)
0.30C + 0.40S = 3100 (Total profit)

From equation 1, we can express S as S = 9000 - C. Substitute this into equation 2: 0.30C + 0.40(9000 - C) = 3100 0.30C + 3600 - 0.40C = 3100 -0.10C = 3100 - 3600 -0.10C = -500 C = -500 / -0.10 C = 5000

The purchase price of the cow (วัว) is 5000 baht. This corresponds to option C.

{"correct_answer_key":"c"}

This is a Thai language question. Here's the translation and explanation:

Translation: "Bought a cow and a sheep for a total of 9,000 baht. Sold the cow for a 30% profit and the sheep for a 40% profit. The total profit was 3,100 baht. Find the price of the cow."

Explanation:

Let 'x' be the cost of the cow and 'y' be the cost of the sheep.

We have two equations:

x + y = 9000
0.3x + 0.4y = 3100

We can solve for x. From equation 1, y = 9000 - x. Substitute this into equation 2:

0.3x + 0.4(9000 - x) = 3100 0.3x + 3600 - 0.4x = 3100 -0.1x = -500 x = 5000

Therefore, the cow cost 5000 baht.

{"correct_answer_key":"c"}

คำอธิบาย:
ให้ราคาวัว = x บาท, ราคาแกะ = y บาท
x + y = 9,000
ขายวัวได้กำไร 30% ⇒ กำไรจากวัว = 0.3x
ขายแกะได้กำไร 40% ⇒ กำไรจากแกะ = 0.4y
รวมกำไร = 0.3x + 0.4y = 3,100

จาก x + y = 9,000 ⇒ y = 9,000 - x
แทนค่าในสมการกำไร:
0.3x + 0.4(9,000 - x) = 3,100
0.3x + 3,600 - 0.4x = 3,100
0.3x - 0.4x = 3,100 - 3,600
-0.1x = -500
x = 5,000

ดังนั้น ราคาวัวที่ซื้อคือ 5,000 บาท

{"correct_answer_key":"c"}

Let's denote the price of the cow as x and the price of the sheep as y.

Given:

x + y = 9000
Profit from cow = 30% of x = 0.3x
Profit from sheep = 40% of y = 0.4y
Total profit = 3100

So, 0.3x + 0.4y = 3100

From the first equation, y = 9000 - x

Substitute into the profit equation: 0.3x + 0.4(9000 - x) = 3100 0.3x + 3600 - 0.4x = 3100 -0.1x + 3600 = 3100 -0.1x = -500 x = 5000

Therefore, the price of the cow is 5000 baht, which corresponds to option C.

{"correct_answer_key":"c"}

จากโจทย์ เรามีข้อมูลดังนี้:

ราคาซื้อวัวและแกะรวมกัน 9,000 บาท
กำไรจากการขายวัว 30%
กำไรจากการขายแกะ 40%
กำไรรวม 3,100 บาท

สมมติ:

ราคาซื้อวัว = x บาท
ราคาซื้อแกะ = 9000 - x บาท

กำไรจากวัว = 30% ของ x = 0.3x
กำไรจากแกะ = 40% ของ (9000 - x) = 0.4(9000 - x)

รวมกำไร = 3,100 บาท
ดังนั้น: 0.3x + 0.4(9000 - x) = 3,100

แก้สมการ: 0.3x + 0.4 * 9000 - 0.4x = 3,100
0.3x - 0.4x + 3600 = 3,100
-0.1x + 3600 = 3,100
-0.1x = 3,100 - 3600
-0.1x = -500
x = -500 / -0.1
x = 5000

ดังนั้น ราคาซื้อวัวตัวละ 5,000 บาท

{"correct_answer_key":"c"}

ขั้นแรก ให้สมมติราคาวัวเป็น ( x ) บาท ดังนั้นราคาแกะจะเป็น ( 9000 - x ) บาท

จากโจทย์:

ขายวัวได้กำไร 30% หมายถึงกำไรจากวัวคือ ( 0.3x )
ขายแกะได้กำไร 40% หมายถึงกำไรจากแกะคือ ( 0.4(9000 - x) )

รวมกำไรทั้งสองอย่างได้ 3,100 บาท ดังนั้นตั้งสมการได้ว่า: [ 0.3x + 0.4(9000 - x) = 3100 ]

แก้สมการ: [ 0.3x + 3600 - 0.4x = 3100 ]

จัดรูปสมการใหม่: [ -0.1x = 3100 - 3600 ]

[ -0.1x = -500 ]

[ x = \frac{-500}{-0.1} = 5000 ]

ดังนั้น ราคาวัวที่ซื้อคือ 5,000 บาท ซึ่งตรงกับตัวเลือกข้อ c

{"correct_answer_key":"c"}

Let's denote the price of the cow as ( x ) and the price of the sheep as ( y ). According to the problem, the total cost is:

[ x + y = 9000 ]

The profit from selling the cow is 30%, so the profit is ( 0.3x ). The profit from selling the sheep is 40%, so the profit is ( 0.4y ). The total profit is given as 3,100 baht:

[ 0.3x + 0.4y = 3100 ]

Now, we have a system of two equations:

( x + y = 9000 )
( 0.3x + 0.4y = 3100 )

We can solve this system to find the value of ( x ).

From the first equation, express ( y ) in terms of ( x ):

[ y = 9000 - x ]

Substitute ( y ) in the second equation:

[ 0.3x + 0.4(9000 - x) = 3100 ]

Simplify and solve for ( x ):

[ 0.3x + 3600 - 0.4x = 3100 ]

[ -0.1x + 3600 = 3100 ]

[ -0.1x = 3100 - 3600 ]

[ -0.1x = -500 ]

[ x = 5000 ]

Therefore, the price of the cow is 5,000 baht, which corresponds to option C.

{"correct_answer_key":"c"}

ให้เราตั้งราคาในการซื้อวัวเป็น ( x ) บาท และราคาในการซื้อแกะเป็น ( 9000 - x ) บาท เนื่องจากราคาทั้งหมดรวมกันเป็น 9,000 บาท

จากข้อมูลที่ให้มา:

กำไรจากการขายวัว = ( 0.3x )
กำไรจากการขายแกะ = ( 0.4(9000 - x) )

รวมกำไรทั้งหมด = ( 0.3x + 0.4(9000 - x) = 3100 )

เราสามารถแก้สมการนี้เพื่อหาค่า ( x ):

( 0.3x + 3600 - 0.4x = 3100 )
( -0.1x + 3600 = 3100 )
( -0.1x = 3100 - 3600 )
( -0.1x = -500 )
( x = 5000 )

ดังนั้น ราคาซื้อวัวคือ 5,000 บาท ซึ่งตรงกับตัวเลือก C

{"correct_answer_key":"c"}

ในการแก้ปัญหานี้ ให้สมมติว่าราคาซื้อวัวคือ (x) บาท ดังนั้นราคาซื้อแกะจะเป็น (9,000 - x) บาท เนื่องจากราคารวมของวัวและแกะคือ 9,000 บาท

กำไรจากการขายวัวคือ 30% ของราคาซื้อวัว = (0.3x)
กำไรจากการขายแกะคือ 40% ของราคาซื้อแกะ = (0.4(9,000 - x))
กำไรรวมทั้งสิ้นคือ (0.3x + 0.4(9,000 - x) = 3,100) บาท

ตั้งสมการ: (0.3x + 0.4(9,000 - x) = 3,100) (0.3x + 3,600 - 0.4x = 3,100) (-0.1x + 3,600 = 3,100) (-0.1x = 3,100 - 3,600) (-0.1x = -500) (x = 5,000)

ดังนั้น ราคาซื้อวัวคือ 5,000 บาท ซึ่งตรงกับตัวเลือก C

{"correct_answer_key":"c"}

First, the question is in Thai. Let me translate it to understand it properly.

"ซื้อวัวและแกะมาอย่างละตัวราคารวมกัน 9,000 บาท" means "Bought one cow and one sheep for a total of 9,000 Baht."

"ขายวัวไปได้กำไร 30%" means "Sold the cow at a 30% profit."

"ขายแกะไปได้กำไร 40%" means "Sold the sheep at a 40% profit."

"รวมกำไรทั้งสิ้น 3,100 บาท" means "Total profit is 3,100 Baht."

We need to find the price of the cow.

Let ( C ) be the cost price of the cow.

Let ( S ) be the cost price of the sheep.

From the problem:

( C + S = 9000 ) (1)

When selling the cow at 30% profit, selling price of cow = ( C + 0.30C = 1.30C )

Profit from cow = Selling price - Cost price = 1.30C - C = 0.30C

For the sheep, sold at 40% profit, selling price of sheep = ( S + 0.40S = 1.40S )

Profit from sheep = 1.40S - S = 0.40S

Total profit = Profit from cow + Profit from sheep = 0.30C + 0.40S = 3100 (2)

So, we have two equations:

( C + S = 9000 )
( 0.30C + 0.40S = 3100 )

I need to solve for C.

From equation 1, S = 9000 - C

Substitute into equation 2:

0.30C + 0.40(9000 - C) = 3100

Let me calculate that:

0.30C + 0.40*9000 - 0.40C = 3100

0.30C + 3600 - 0.40C = 3100

Combine like terms: (0.30C - 0.40C) + 3600 = 3100

-0.10C + 3600 = 3100

Subtract 3600 from both sides:

-0.10C = 3100 - 3600

-0.10C = -500

Divide both sides by -0.10:

C = (-500) / (-0.10)

C = 5000

So, the cost price of the cow is 5000 Baht.

Now, looking at the options:

a: 3000

b: 4000

c: 5000

d: 6000

e: 7000

The correct answer is c: 5000

I need to provide a brief explanation and then respond in JSON with the "correct_answer_key".

Brief explanation: John bought a cow and a sheep for 9000 Baht total. He sold the cow at 30% profit and the sheep at 40% profit, making a total profit of 3100 Baht. Solving the equations, the cow costs 5000 Baht.

Finally, output in JSON: {"correct_answer_key":"c"}

Explanation:

คุณซื้อวัวและแกะอย่างละตัวในราคารวม 9,000 บาท โดยขายวัวได้กำไร 30% และขายแกะได้กำไร 40% รวมกำไรทั้งหมด 3,100 บาท เราสามารถตั้งสมการได้ดังนี้:

ให้ ( C ) เป็นราคาซื้อวัว และ ( S ) เป็นราคาซื้อแกะ
( C + S = 9000 )
กำไรจากวัว = 0.30C, กำไรจากแกะ = 0.40S
รวมกำไร: ( 0.30C + 0.40S = 3100 )

แก้สมการโดยแทน ( S = 9000 - C ) เข้าไป:
( 0.30C + 0.40(9000 - C) = 3100 )
( 0.30C + 3600 - 0.40C = 3100 )
( -0.10C + 3600 = 3100 )
( -0.10C = -500 )
( C = 5000 )

ดังนั้น ราคาซื้อวัวคือ 5,000 บาท ซึ่งตรงกับตัวเลือก c.

{"correct_answer_key":"c"}

Let's denote the cost of the cow as C and the cost of the sheep as S. We know that C + S = 9000.

The profit from selling the cow is 30% of its cost, which is 0.3C. The profit from selling the sheep is 40% of its cost, which is 0.4S. The total profit is 3100, so we can set up the equation:

0.3C + 0.4S = 3100

We also know that C + S = 9000, so we can express S as 9000 - C and substitute it into the first equation:

0.3C + 0.4(9000 - C) = 3100

Expanding and simplifying the equation:

0.3C + 3600 - 0.4C = 3100

Combine like terms:

-0.1C = -500

Divide by -0.1:

C = 5000

So, the cost of the cow is 5000.

{"correct_answer_key":"c"}

Let's denote the cost of the cow as (C) and the cost of the sheep as (S). We are given that (C + S = 9000).

The profit from selling the cow at a 30% profit is (0.3C), and the profit from selling the sheep at a 40% profit is (0.4S). The total profit is given as 3100, so (0.3C + 0.4S = 3100).

From the first equation, we can express (S) as (S = 9000 - C).

Substituting (S) in the second equation gives us (0.3C + 0.4(9000 - C) = 3100).

Simplifying, we get (0.3C + 3600 - 0.4C = 3100), which simplifies further to (-0.1C = -500).

Dividing both sides by -0.1 gives (C = 5000).

Therefore, the cost of the cow is 5000, which corresponds to option C.

{"correct_answer_key":"c"}

Let's break down the problem:

ซื้อวัวและแกะมาอย่างละตัวราคารวมกัน 9,000 บาท (The total cost of a cow and a sheep is 9,000 baht)
สมมติว่าราคาวัวคือ x บาท และราคาแกะคือ 9,000 - x บาท (Let's assume the cost of a cow is x baht and the cost of a sheep is 9,000 - x baht)
ขายวัวไปได้กำไร 30% ดังนั้นราคาขายวัวคือ 1.3x บาท (The cow is sold at a 30% profit, so the selling price is 1.3x baht)
ขายแกะไปได้กำไร 40% ดังนั้นราคาขายแกะคือ 1.4(9,000 - x) บาท (The sheep is sold at a 40% profit, so the selling price is 1.4(9,000 - x) baht)
รวมกำไรทั้งสิ้น 3,100 บาท ดังนั้น (1.3x - x) + (1.4(9,000 - x) - (9,000 - x)) = 3,100 (The total profit is 3,100 baht)
0.3x + 0.4(9,000 - x) = 3,100
0.3x + 3,600 - 0.4x = 3,100
-0.1x = -500
x = 5,000

ดังนั้น ราคาวัวคือ 5,000 บาท

{"correct_answer_key":"c"}

This problem involves setting up an equation based on the given information about the purchase and sale of a cow and a goat.

Let ( C ) be the cost of the cow and ( G ) be the cost of the goat. We know:

( C + G = 9000 ) (total cost)
The profit from selling the cow is 30%, so the selling price of the cow is ( C + 0.3C = 1.3C ).
The profit from selling the goat is 40%, so the selling price of the goat is ( G + 0.4G = 1.4G ).
The total profit from selling both is 3100 baht.

The profit from selling the cow is ( 0.3C ) and from the goat is ( 0.4G ). Thus, the total profit equation is: [ 0.3C + 0.4G = 3100 ]

We now have a system of linear equations:

( C + G = 9000 )
( 0.3C + 0.4G = 3100 )

To solve for ( C ) and ( G ), we can use substitution or elimination. Let's use substitution:

From the first equation: [ G = 9000 - C ]

Substitute ( G ) into the second equation: [ 0.3C + 0.4(9000 - C) = 3100 ] [ 0.3C + 3600 - 0.4C = 3100 ] [ -0.1C + 3600 = 3100 ] [ -0.1C = 3100 - 3600 ] [ -0.1C = -500 ] [ C = \frac{-500}{-0.1} ] [ C = 5000 ]

So the cost of the cow is 5000 baht, which corresponds to option C.

{"correct_answer_key":"c"}

คำอธิบายโดยย่อ:
กำหนดให้ราคาซื้อวัว = x และราคาซื้อแกะ = y โดย x + y = 9000 และได้กำไรจากวัว 30% (0.30x) และกำไรจากแกะ 40% (0.40y) รวมกำไร 3,100 ตามสมการ 0.30x + 0.40y = 3,100 เมื่อนำ y=9000−x แทนลงไปและแก้สมการจะได้ x=5,000

ดังนั้นราคาซื้อวัวคือ 5,000 บาท

ตอบ:
{"correct_answer_key":"c"}

ให้ x = ราคาที่ซื้อวัว (บาท) และ y = ราคาที่ซื้อแกะ (บาท)

x + y = 9,000 (ราคารวม)
กำไรรวม = 0.30x + 0.40y = 3,100

แทน y = 9,000 − x ในสมการกำไร: 0.30x + 0.40(9,000 − x) = 3,100
0.30x + 3,600 − 0.40x = 3,100
−0.10x = −500
x = 5,000

ดังนั้นราคาที่ซื้อวัวคือ 5,000 บาท ตรงกับตัวเลือก c.

{"correct_answer_key":"c"}

ต้นทุนวัว = x บาท, ต้นทุนแกะ = y บาท

x + y = 9,000
กำไรรวม 0.30x + 0.40y = 3,100

แทน y = 9,000 − x ใน (2):
0.30x + 0.40(9,000 − x) = 3,100
0.30x + 3,600 − 0.40x = 3,100
−0.10x = −500 → x = 5,000

ดังนั้นราคาต้นทุนวัวคือ 5,000 บาท (ตัวเลือก c)

{"correct_answer_key":"c"}

ตั้งสมมุติให้ราคาซื้อวัว = x บาท จึงได้ราคาซื้อแกะ = 9000 − x บาท

กำไรวัว = 30% ของ x = 0.30x
กำไรแกะ = 40% ของ (9000 − x) = 0.40(9000 − x)

รวมกำไร 3100 บาท
0.30x + 0.40(9000 − x) = 3100
0.30x + 3600 − 0.40x = 3100
−0.10x = −500
x = 5000

ดังนั้น ราคาซื้อวัว = 5,000 บาท ตรงกับข้อ c

{"correct_answer_key":"c"}

Let the cost of the cow be x and the sheep be (9000 - x). The profit from the cow is 30% of x (0.3x) and from the sheep is 40% of (9000 - x) (0.4(9000 - x)). The total profit is:

0.3x + 0.4(9000 - x) = 3100

Expanding, we have:

0.3x + 3600 - 0.4x = 3100
-0.1x + 3600 = 3100
-0.1x = -500
x = 5000

Thus, the cow was purchased for 5,000 baht.

{"correct_answer_key": "c"}

Let the cost of the cow be x and the cost of the sheep be y. We know that x + y = 9,000. The profit from the cow is 30% of x (i.e., 0.30x) and from the sheep is 40% of y (i.e., 0.40y). The total profit is given as 3,100 baht:

0.30x + 0.40y = 3,100

Substitute y = 9,000 - x into the profit equation:

0.30x + 0.40(9,000 - x) = 3,100
0.30x + 3,600 - 0.40x = 3,100
-0.10x + 3,600 = 3,100
-0.10x = -500
x = 5,000

Thus, the cost of the cow is 5,000 baht, which corresponds to option C.

{"correct_answer_key": "c"}

เรากำหนดให้ราคาวัว = x บาท และราคากแกะ = 9000 – x บาท จากนั้นกำไรจากการขายวัว = 0.3x และกำไรจากการขายแกะ = 0.4(9000 – x) รวมกำไรที่ได้คือ 0.3x + 0.4(9000 – x) = 3100 0.3x + 3600 – 0.4x = 3100 –0.1x = 3100 – 3600 = –500 ⇒ x = 5000 บาท ดังนั้นราคาวัวที่ซื้อมีราคา 5,000 บาท ซึ่งตรงกับตัวเลือก c

{"correct_answer_key": "c"}

สมมติราคาซื้อวัว = x และแกะ = y เมื่อ x + y = 9,000
กำไรจากวัว = 0.3x, กำไรจากแกะ = 0.4y รวม 3,100
แทน y = 9,000 – x ลงใน 0.3x + 0.4(9,000 – x) = 3,100
แก้ได้ x = 5,000

{"correct_answer_key":"c"}

สมมติราคาซื้อวัว = x บาท แกะ = 9000−x บาท
กำไรรวม = 30%x + 40%(9000−x) = 3100
0.3x + 3600 − 0.4x = 3100 → −0.1x = −500 → x = 5000 บาท

{"correct_answer_key":"c"}

วางราคาซื้อวัว = x บาท, ซื้อแกะ = 9000 − x บาท
กำไร = 30% ของ x + 40% ของ (9000−x) = 0.3x + 0.4(9000−x) = 3100
→ 0.3x + 3600 − 0.4x = 3100
→ −0.1x = −500 ⇒ x = 5000

{"correct_answer_key":"c"}

Let's denote the price of a cow as ( x ) and the price of a sheep as ( y ). We have the following equations based on the problem:

( x + y = 9,000 ) (total cost of one cow and one sheep)
( 0.3x + 0.4y = 3,100 ) (total profit from selling one cow and one sheep)

We need to solve these equations to find the value of ( x ).

From equation 1, we can express ( y ) in terms of ( x ):

[ y = 9,000 - x ]

Substitute ( y ) in equation 2:

[ 0.3x + 0.4(9,000 - x) = 3,100 ]

Simplify and solve for ( x ):

[ 0.3x + 3,600 - 0.4x = 3,100 ]

[ -0.1x + 3,600 = 3,100 ]

[ -0.1x = 3,100 - 3,600 ]

[ -0.1x = -500 ]

[ x = \frac{-500}{-0.1} ]

[ x = 5,000 ]

Thus, the price of a cow is 5,000 baht, which corresponds to option C.

{"correct_answer_key":"c"}

Explanation:

Let the price of the cow be $ x $ baht and the price of the sheep be $ y $ baht. From the problem:

The total cost of both animals is 9,000 baht: $$ x + y = 9000 $$
The total profit from selling both animals is 3,100 baht. The cow is sold at a 30% profit, and the sheep is sold at a 40% profit: $$ 0.3x + 0.4y = 3100 $$

We now solve this system of equations:

Step 1: Solve for $ y $ in terms of $ x $ using the first equation:

$$ y = 9000 - x $$

Step 2: Substitute $ y = 9000 - x $ into the second equation:

$$ 0.3x + 0.4(9000 - x) = 3100 $$

Simplify: $$ 0.3x + 3600 - 0.4x = 3100 $$

Combine like terms: $$ -0.1x + 3600 = 3100 $$

Solve for $ x $: $$ -0.1x = 3100 - 3600 $$ $$ -0.1x = -500 $$ $$ x = 5000 $$

Step 3: Verify the solution:

If $ x = 5000 $, then $ y = 9000 - 5000 = 4000 $.

Profit from selling the cow: $ 0.3 \times 5000 = 1500 $ baht.
Profit from selling the sheep: $ 0.4 \times 4000 = 1600 $ baht.
Total profit: $ 1500 + 1600 = 3100 $ baht, which matches the problem statement.

Thus, the price of the cow is 5,000 baht, corresponding to option C.

Final Answer:

{"correct_answer_key":"c"}

Okay, let's tackle this problem step by step. So, the question is in Thai, but I'll try to parse it out. The problem says:

"Buying a cow and a sheep each for a total of 9,000 baht. Selling the cow at a 30% profit and the sheep at a 40% profit, resulting in a total profit of 3,100 baht. Find the price of the cow per head."

Alright, so we need to find the cost price of the cow. Let's denote variables for the cow and sheep's costs. Let me set this up.

Let’s let the cost of the cow be C baht, and the cost of the sheep be S baht. According to the problem, together they cost 9,000 baht. So the first equation is straightforward:

C + S = 9000.

Now, the profits. The cow is sold at a 30% profit, so the selling price of the cow is C plus 30% of C, which is 1.3C. Similarly, the sheep is sold at a 40% profit, so its selling price is 1.4S. The total profit from both is 3,100 baht.

Wait, profit is selling price minus cost price. So total profit would be (1.3C - C) + (1.4S - S) = 0.3C + 0.4S = 3100.

So now we have two equations:

C + S = 9000
0.3C + 0.4S = 3100

We can solve this system of equations. Let me express S from the first equation: S = 9000 - C. Then substitute into the second equation.

0.3C + 0.4*(9000 - C) = 3100.

Let me compute that step by step. Expanding the second term:

0.3C + 0.4*9000 - 0.4C = 3100

Calculate 0.4*9000: that's 3600.

So, 0.3C - 0.4C + 3600 = 3100

Combine like terms: -0.1C + 3600 = 3100

Subtract 3600 from both sides: -0.1C = 3100 - 3600 = -500

Then, divide both sides by -0.1: C = (-500)/(-0.1) = 5000.

So the cow's cost is 5,000 baht. Let me check the options. The options are a)3000, b)4000, c)5000, d)6000, e)7000. So the answer should be option c)5000.

Wait, let me verify again to be sure. If the cow is 5000, then the sheep is 4000 (since 5000+4000=9000).

Profit on cow: 30% of 5000 = 1500.

Profit on sheep:40% of 4000 = 1600.

Total profit:1500+1600=3100. Exactly matches the given total profit. So that's correct. Therefore, the answer is c)5000.

The problem involves setting up equations based on the total cost and total profit. Let the cow's cost be ( C ) and the sheep's cost be ( S ). We have:

( C + S = 9000 )
Profit equations: ( 0.3C + 0.4S = 3100 ).

Substituting ( S = 9000 - C ) into the second equation:
( 0.3C + 0.4(9000 - C) = 3100 ).
Simplifying gives ( -0.1C + 3600 = 3100 ), leading to ( C = 5000 ).

Verification:

Cow profit: ( 30% \times 5000 = 1500 ).
Sheep profit: ( 40% \times 4000 = 1600 ).
Total profit: ( 1500 + 1600 = 3100 ), which matches.

{"correct_answer_key":"c"}

Let's denote the cost of the cow as C and the cost of the sheep as S. We know that C + S = 9000.

The profit from selling the cow is 30% of C, which is 0.3C. The profit from selling the sheep is 40% of S, which is 0.4S. The total profit is 3100, so we have the equation 0.3C + 0.4S = 3100.

We can express S in terms of C from the first equation: S = 9000 - C. Substituting this into the second equation gives 0.3C + 0.4(9000 - C) = 3100.

Simplifying this equation, we get 0.3C + 3600 - 0.4C = 3100, which simplifies to -0.1C = -500, so C = 5000.

So, the cost of the cow is 5000 baht, which corresponds to option C.

{"correct_answer_key":"c"}

Alright! Let's tackle this problem step by step. The user provided a question in Thai about buying an ox and a sheep, each at different prices, with a total cost of 9,000 baht. They sold both for a profit: 30% on the ox and 40% on the sheep, making a total profit of 3,100 baht. The question is asking for the cost price of the ox.

First, I need to understand the problem clearly. There are two items: an ox and a sheep. Each was bought for a certain price, and their total cost is 9,000 baht. When sold, the ox made a 30% profit, and the sheep made a 40% profit. The combined profit from both sales is 3,100 baht. We need to find out how much the ox originally cost.

Let me denote the cost price of the ox as 'C' baht and the cost price of the sheep as 'S' baht. According to the problem, the total cost is 9,000 baht, so:

C + S = 9,000

That's our first equation.

Next, we know the profit from selling the ox is 30% of its cost price, which is 0.3C. Similarly, the profit from selling the sheep is 40% of its cost price, which is 0.4S. The total profit from both sales is 3,100 baht, so:

0.3C + 0.4S = 3,100

That's our second equation.

Now, we have a system of two equations with two variables:

C + S = 9,000
0.3C + 0.4S = 3,100

I need to solve this system to find the value of C (the cost of the ox).

One common method to solve such systems is substitution or elimination. Let's try substitution.

From the first equation, we can express S in terms of C:

S = 9,000 - C

Now, substitute this expression for S into the second equation:

0.3C + 0.4(9,000 - C) = 3,100

Let's compute this step by step.

First, expand the second term:

0.49,000 = 3,600 0.4(-C) = -0.4*C

So, the equation becomes:

0.3C + 3,600 - 0.4C = 3,100

Combine like terms:

(0.3C - 0.4C) + 3,600 = 3,100 -0.1*C + 3,600 = 3,100

Now, subtract 3,600 from both sides:

-0.1C = 3,100 - 3,600 -0.1C = -500

Multiply both sides by -10 to solve for C:

C = (-500)*(-10) C = 5,000

So, the cost price of the ox is 5,000 baht.

Looking back at the options provided: a: 3000 b: 4000 c: 5000 d: 6000 e: 7000

The correct answer is option c: 5000.

{"correct_answer_key":"c"}

TPAT-1 Tests - เชาวน์ปัญญา - [13]

Question

Answers by AI

Explanation:

Answer in JSON:

Explanation:

Explanation:

Step 1: Solve for $ y $ in terms of $ x $ using the first equation:

Step 2: Substitute $ y = 9000 - x $ into the second equation:

Step 3: Verify the solution:

Final Answer:

TPAT-1 Tests - เชาวน์ปัญญา - [13]

Question

Answers by AI

C claude-3-5-sonnet-20241022 186 new bootstrap.Tooltip(document.getElementById("😭2"));

C claude-3-7-sonnet-20250219 211 new bootstrap.Tooltip(document.getElementById("😭3"));

C claude-3-7-sonnet-20250219[thinking=16k] 709 new bootstrap.Tooltip(document.getElementById("😭4"));

C command-a-03-2025 467 new bootstrap.Tooltip(document.getElementById("😭5"));

C deepseek-chat-v3-0324 290 new bootstrap.Tooltip(document.getElementById("😭6"));

Explanation:

Answer in JSON:

C deepseek-r1 563 new bootstrap.Tooltip(document.getElementById("😭7"));

C gemini-1.5-pro-002 303 new bootstrap.Tooltip(document.getElementById("😭8"));

C gemini-2.0-flash-001 190 new bootstrap.Tooltip(document.getElementById("😭9"));

C gemini-2.0-flash-lite-001 270 new bootstrap.Tooltip(document.getElementById("😭10"));

C gemini-2.0-flash-thinking-exp-01-21 248 new bootstrap.Tooltip(document.getElementById("😭11"));

C gemini-2.5-flash-preview-04-17 1059 new bootstrap.Tooltip(document.getElementById("😭12"));

C gemini-2.5-flash-preview-04-17[no-thinking] 319 new bootstrap.Tooltip(document.getElementById("😭13"));

C gemini-2.5-pro-preview-03-25 1366 new bootstrap.Tooltip(document.getElementById("😭14"));

C gemma-3-27b-it 270 new bootstrap.Tooltip(document.getElementById("😭15"));

C gpt-4.1-2025-04-14 233 new bootstrap.Tooltip(document.getElementById("😭16"));

C gpt-4.1-mini-2025-04-14 208 new bootstrap.Tooltip(document.getElementById("😭17"));

C gpt-4.1-nano-2025-04-14 302 new bootstrap.Tooltip(document.getElementById("😭18"));

C gpt-4.5-preview-2025-02-27 261 new bootstrap.Tooltip(document.getElementById("😭19"));

C gpt-4o-2024-08-06 350 new bootstrap.Tooltip(document.getElementById("😭20"));

C gpt-4o-mini-2024-07-18 254 new bootstrap.Tooltip(document.getElementById("😭21"));

C grok-3-beta 301 new bootstrap.Tooltip(document.getElementById("😭22"));

C grok-3-mini-beta[thinking] 283 new bootstrap.Tooltip(document.getElementById("😭23"));

Explanation:

C llama-3.3-70b-instruct 231 new bootstrap.Tooltip(document.getElementById("😭24"));

C llama-4-maverick 242 new bootstrap.Tooltip(document.getElementById("😭25"));

C llama-4-scout 352 new bootstrap.Tooltip(document.getElementById("😭26"));

C mistral-large-2411 515 new bootstrap.Tooltip(document.getElementById("😭27"));

C o1-2024-12-17 605 new bootstrap.Tooltip(document.getElementById("😭28"));

C o3-2025-04-16[high] 639 new bootstrap.Tooltip(document.getElementById("😭29"));

C o3-2025-04-16[low] 430 new bootstrap.Tooltip(document.getElementById("😭30"));

C o3-2025-04-16[medium] 384 new bootstrap.Tooltip(document.getElementById("😭31"));

C o3-mini-2025-01-31[high] 954 new bootstrap.Tooltip(document.getElementById("😭32"));

C o3-mini-2025-01-31[low] 553 new bootstrap.Tooltip(document.getElementById("😭33"));

C o3-mini-2025-01-31[medium] 621 new bootstrap.Tooltip(document.getElementById("😭34"));

C o4-mini-2025-04-16[high] 641 new bootstrap.Tooltip(document.getElementById("😭35"));

C o4-mini-2025-04-16[low] 491 new bootstrap.Tooltip(document.getElementById("😭36"));

C o4-mini-2025-04-16[medium] 386 new bootstrap.Tooltip(document.getElementById("😭37"));

C phi-4 306 new bootstrap.Tooltip(document.getElementById("😭38"));

C qwen-max-2025-01-25 513 new bootstrap.Tooltip(document.getElementById("😭39"));

Explanation:

Step 1: Solve for $ y $ in terms of $ x $ using the first equation:

Step 2: Substitute $ y = 9000 - x $ into the second equation:

Step 3: Verify the solution:

Final Answer:

C qwq-32b 1056 new bootstrap.Tooltip(document.getElementById("😭40"));

C typhoon-v2-70b-instruct 232 new bootstrap.Tooltip(document.getElementById("😭41"));

C typhoon-v2-r1-70b-preview 718 new bootstrap.Tooltip(document.getElementById("😭42"));